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3x^2-35x+78=0
a = 3; b = -35; c = +78;
Δ = b2-4ac
Δ = -352-4·3·78
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-17}{2*3}=\frac{18}{6} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+17}{2*3}=\frac{52}{6} =8+2/3 $
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